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6y=8y^2-15
We move all terms to the left:
6y-(8y^2-15)=0
We get rid of parentheses
-8y^2+6y+15=0
a = -8; b = 6; c = +15;
Δ = b2-4ac
Δ = 62-4·(-8)·15
Δ = 516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{516}=\sqrt{4*129}=\sqrt{4}*\sqrt{129}=2\sqrt{129}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{129}}{2*-8}=\frac{-6-2\sqrt{129}}{-16} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{129}}{2*-8}=\frac{-6+2\sqrt{129}}{-16} $
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